Armature Torque of D.C. Motor

Torque is the turning moment of a force about an axis and is measured by the product of force (F) and radius (r) at right angle to which the force acts i.e.
D.C. Motors torque
T = F × r

In a d.c. motor, each conductor is acted upon by a circumferential force F at a distance r, the radius of the armature (Fig. 4.8). Therefore, each conductor exerts a torque, tending to rotate the armature. The sum of the torques due to all armature conductors is known as gross or armature torque (T_a).

Let in a d.c. motor

r = average radius of armature in m
l = effective length of each conductor in m

Z = total number of armature conductors

A = number of parallel paths

i = current in each conductor = I_a/A
B = average flux density in Wb/m²
Φ = flux per pole in Wb
P = number of poles

Force on each conductor, F = B i l newtons

Torque due to one conductor = F × r newton- metre
Total armature torque, T_a = Z F r newton-metre
= Z B i l r

Now i = I_a/A, B = Φ/a where a is the x-sectional area of flux path per pole at
radius r. Clearly, a = 2πr l /P.

T_a = Z × (Ф/a)×( I_a/A)×l×r

T_a = Z × (ФP/2πr l)×( I_a/A)×l×r = Z Ф I_aP/(2πA) N-m

or T_a = 0.159Z Ф I_a(P/A) N-m……………………………………(i)

so Ta

T_a α Ф I_a

Hence torque in a d.c. motor is directly proportional to flux per pole and
armature current.

(i) For a shunt motor, flux Φ is practically constant.

T_a α  I_a

(ii) For a series motor, flux Φ is directly proportional to armature current I_a
provided magnetic saturation does not take place.

T_a α I_a²

up to magnetic saturation

Alternative expression for Ta

E_b = PФZN/60A

(60×E_b) /N= PФZ/A

From Eq.(i), we get the expression of Ta as:

T_a =0.159×(60× E_b/N)× I_a

T_a =9.55×( E_bI_a/N)

Note that developed torque or gross torque means armature torque Ta.